Appendix I: Omissions#
Appendix I.I: Omitted Axioms#
This section of the Appendix contains Axioms the author considered at various points during the formalization, but as they did not ultimately seem necessary to establish the main results of the work, they have been placed here.
Note
The Duality Axioms are reminiscent of the relation of surjectivity in real analysis. However, containment is not a strict equality relation so this resemblance should not be taken too far.
This Axiom is required to induce proofs about Word Length. Without it, there is no formal way to accomplish an induction over Word Length. However, it may be (justifiably) argued there is no reason a natural language should obey this rule. It is possible to conceive of a natural language that does not have sentences with, say, exactly \(n = 13\) words, perhaps due to an eccentricity in its grammar. In natural languages such as these, the results that depend on the following theorem are only valid in a truncated Corpus where all sentences with \(\Lambda(\zeta) > 12\) are ignored.
Appendix I.II: Omitted Proofs#
Note
Numbered theorems in this appendix are directly referenced in the main. An x in the theorem title indicates the theorem does not fit into the natural flow of the paper.
Section I.II#
Proof Follows directly from Theorem 1.2.3 by the law of contraposition.
∎
Section I.IV#
Proof Let \(s \in S\). Let \(n = l(s)\). Let \(i \in N_n\). The proof proceeds by induction on \(i\).
Basis: \(i = 1\)
By definition of Left Partial Strings,
Induction:
Proof Let \(s \in S\). Let \(n = l(s)\). Consider \(s[i:]\) with \(i \in N_n\). Let
Then \(j \in N_n\), since \(i = 1 \implies j = n\) and \(i = n \implies j = 1\). The proof proceeds by induction on \(j\).
Basis
Induction
Section II.I#
Proof Follows immediately from Theorem 2.2.4 by the law of contraposition.
∎
Section II.IV#
Proof Follow directly from Theorem 2-4-1,
By Theorem 2.4.8,
Thus,
But this is exactly the definition of set intersections. Therefore,
But this is exactly the definition of subsets,